Base | Representation |
---|---|
bin | 1110111011111111001… |
… | …11010111010000001111 |
3 | 1211001202201121210110010 |
4 | 13131333213113100033 |
5 | 31402104441233034 |
6 | 1031440304044303 |
7 | 52036422103533 |
oct | 7357747272017 |
9 | 1731681553403 |
10 | 513242133519 |
11 | 1887348933a5 |
12 | 83577903693 |
13 | 3952473973b |
14 | 1ababbbbbc3 |
15 | d53d4633e9 |
hex | 777f9d740f |
513242133519 has 4 divisors (see below), whose sum is σ = 684322844696. Its totient is φ = 342161422344.
The previous prime is 513242133491. The next prime is 513242133581. The reversal of 513242133519 is 915331242315.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 513242133519 - 212 = 513242129423 is a prime.
It is a super-2 number, since 2×5132421335192 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513242133619) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85540355584 + ... + 85540355589.
It is an arithmetic number, because the mean of its divisors is an integer number (171080711174).
Almost surely, 2513242133519 is an apocalyptic number.
513242133519 is a deficient number, since it is larger than the sum of its proper divisors (171080711177).
513242133519 is a wasteful number, since it uses less digits than its factorization.
513242133519 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171080711176.
The product of its digits is 97200, while the sum is 39.
The spelling of 513242133519 in words is "five hundred thirteen billion, two hundred forty-two million, one hundred thirty-three thousand, five hundred nineteen".
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