Base | Representation |
---|---|
bin | 10111010101110000101110… |
… | …00001011110111011100011 |
3 | 20201201122102121021120000212 |
4 | 23222320113001132323203 |
5 | 23211403100313431003 |
6 | 301054254154404335 |
7 | 13545061300044425 |
oct | 1352702701367343 |
9 | 221648377246025 |
10 | 51325245452003 |
11 | 15398a07013aa6 |
12 | 590b214a306ab |
13 | 2283c46b631a3 |
14 | c96225990815 |
15 | 5e014a08ddd8 |
hex | 2eae1705eee3 |
51325245452003 has 4 divisors (see below), whose sum is σ = 51453238583208. Its totient is φ = 51197252320800.
The previous prime is 51325245451999. The next prime is 51325245452017. The reversal of 51325245452003 is 30025454252315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51325245452003 - 22 = 51325245451999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51325245452203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63996565001 + ... + 63996565802.
It is an arithmetic number, because the mean of its divisors is an integer number (12863309645802).
Almost surely, 251325245452003 is an apocalyptic number.
51325245452003 is a deficient number, since it is larger than the sum of its proper divisors (127993131205).
51325245452003 is a wasteful number, since it uses less digits than its factorization.
51325245452003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 127993131204.
The product of its (nonzero) digits is 720000, while the sum is 41.
The spelling of 51325245452003 in words is "fifty-one trillion, three hundred twenty-five billion, two hundred forty-five million, four hundred fifty-two thousand, three".
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