Base | Representation |
---|---|
bin | 101111110011100000… |
… | …111101011111110001 |
3 | 11220111021201111111101 |
4 | 233303200331133301 |
5 | 1320111004103431 |
6 | 35325235044401 |
7 | 3465003012205 |
oct | 576340753761 |
9 | 156437644441 |
10 | 51330144241 |
11 | 1a85058a112 |
12 | 9b46440701 |
13 | 4ac050051c |
14 | 26ad25ab05 |
15 | 150653b961 |
hex | bf383d7f1 |
51330144241 has 4 divisors (see below), whose sum is σ = 54031730800. Its totient is φ = 48628557684.
The previous prime is 51330144227. The next prime is 51330144247. The reversal of 51330144241 is 14244103315.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51330144241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51330144247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1350793251 + ... + 1350793288.
It is an arithmetic number, because the mean of its divisors is an integer number (13507932700).
Almost surely, 251330144241 is an apocalyptic number.
It is an amenable number.
51330144241 is a deficient number, since it is larger than the sum of its proper divisors (2701586559).
51330144241 is a wasteful number, since it uses less digits than its factorization.
51330144241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2701586558.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 51330144241 its reverse (14244103315), we get a palindrome (65574247556).
The spelling of 51330144241 in words is "fifty-one billion, three hundred thirty million, one hundred forty-four thousand, two hundred forty-one".
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