Base | Representation |
---|---|
bin | 1110111100001000111… |
… | …00000101110101111101 |
3 | 1211001222100220112011022 |
4 | 13132010130011311331 |
5 | 31402241201032301 |
6 | 1031452314433525 |
7 | 52041424025516 |
oct | 7360434056575 |
9 | 1731870815138 |
10 | 513323064701 |
11 | 188776540177 |
12 | 8359aa328a5 |
13 | 39538434905 |
14 | 1abb8847a0d |
15 | d5455ecd1b |
hex | 7784705d7d |
513323064701 has 2 divisors, whose sum is σ = 513323064702. Its totient is φ = 513323064700.
The previous prime is 513323064697. The next prime is 513323064707. The reversal of 513323064701 is 107460323315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 320470342201 + 192852722500 = 566101^2 + 439150^2 .
It is a cyclic number.
It is not a de Polignac number, because 513323064701 - 22 = 513323064697 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513323064707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256661532350 + 256661532351.
It is an arithmetic number, because the mean of its divisors is an integer number (256661532351).
Almost surely, 2513323064701 is an apocalyptic number.
It is an amenable number.
513323064701 is a deficient number, since it is larger than the sum of its proper divisors (1).
513323064701 is an equidigital number, since it uses as much as digits as its factorization.
513323064701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45360, while the sum is 35.
The spelling of 513323064701 in words is "five hundred thirteen billion, three hundred twenty-three million, sixty-four thousand, seven hundred one".
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