Base | Representation |
---|---|
bin | 100101010110011001010… |
… | …0010100110110011001011 |
3 | 200011202000212021120022112 |
4 | 1022230302202212303023 |
5 | 1133101031431220324 |
6 | 14530115423412535 |
7 | 1036604540540531 |
oct | 112546242466313 |
9 | 20152025246275 |
10 | 5133333851339 |
11 | 16aa042151531 |
12 | 6aaa5b15414b |
13 | 2b30c08710a5 |
14 | 13a651920151 |
15 | 8d7e30c2c0e |
hex | 4ab328a6ccb |
5133333851339 has 2 divisors, whose sum is σ = 5133333851340. Its totient is φ = 5133333851338.
The previous prime is 5133333851231. The next prime is 5133333851341. The reversal of 5133333851339 is 9331583333315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5133333851339 - 216 = 5133333785803 is a prime.
It is a super-2 number, since 2×51333338513392 (a number of 26 digits) contains 22 as substring.
Together with 5133333851341, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5133333854339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566666925669 + 2566666925670.
It is an arithmetic number, because the mean of its divisors is an integer number (2566666925670).
Almost surely, 25133333851339 is an apocalyptic number.
5133333851339 is a deficient number, since it is larger than the sum of its proper divisors (1).
5133333851339 is an equidigital number, since it uses as much as digits as its factorization.
5133333851339 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3936600, while the sum is 50.
The spelling of 5133333851339 in words is "five trillion, one hundred thirty-three billion, three hundred thirty-three million, eight hundred fifty-one thousand, three hundred thirty-nine".
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