Base | Representation |
---|---|
bin | 10111010101111111111101… |
… | …00001011110001110010011 |
3 | 20201202102112121022012202011 |
4 | 23222333332201132032103 |
5 | 23212021323112420112 |
6 | 301102125524403351 |
7 | 13545501052340461 |
oct | 1352777641361623 |
9 | 221672477265664 |
10 | 51333424341907 |
11 | 153a1423866044 |
12 | 5910917b46557 |
13 | 228494b47bb06 |
14 | c9679dd03831 |
15 | 5e0478123aa7 |
hex | 2eaffe85e393 |
51333424341907 has 2 divisors, whose sum is σ = 51333424341908. Its totient is φ = 51333424341906.
The previous prime is 51333424341883. The next prime is 51333424341917. The reversal of 51333424341907 is 70914342433315.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51333424341907 is a prime.
It is not a weakly prime, because it can be changed into another prime (51333424341917) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25666712170953 + 25666712170954.
It is an arithmetic number, because the mean of its divisors is an integer number (25666712170954).
Almost surely, 251333424341907 is an apocalyptic number.
51333424341907 is a deficient number, since it is larger than the sum of its proper divisors (1).
51333424341907 is an equidigital number, since it uses as much as digits as its factorization.
51333424341907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3265920, while the sum is 49.
The spelling of 51333424341907 in words is "fifty-one trillion, three hundred thirty-three billion, four hundred twenty-four million, three hundred forty-one thousand, nine hundred seven".
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