Base | Representation |
---|---|
bin | 10111010101111111111101… |
… | …00001011110001110011101 |
3 | 20201202102112121022012202112 |
4 | 23222333332201132032131 |
5 | 23212021323112420132 |
6 | 301102125524403405 |
7 | 13545501052340504 |
oct | 1352777641361635 |
9 | 221672477265675 |
10 | 51333424341917 |
11 | 153a1423866053 |
12 | 5910917b46565 |
13 | 228494b47bb13 |
14 | c9679dd0383b |
15 | 5e0478123ab2 |
hex | 2eaffe85e39d |
51333424341917 has 2 divisors, whose sum is σ = 51333424341918. Its totient is φ = 51333424341916.
The previous prime is 51333424341907. The next prime is 51333424341919. The reversal of 51333424341917 is 71914342433315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50796210105316 + 537214236601 = 7127146^2 + 732949^2 .
It is a cyclic number.
It is not a de Polignac number, because 51333424341917 - 210 = 51333424340893 is a prime.
Together with 51333424341919, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51333424341919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25666712170958 + 25666712170959.
It is an arithmetic number, because the mean of its divisors is an integer number (25666712170959).
Almost surely, 251333424341917 is an apocalyptic number.
It is an amenable number.
51333424341917 is a deficient number, since it is larger than the sum of its proper divisors (1).
51333424341917 is an equidigital number, since it uses as much as digits as its factorization.
51333424341917 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3265920, while the sum is 50.
The spelling of 51333424341917 in words is "fifty-one trillion, three hundred thirty-three billion, four hundred twenty-four million, three hundred forty-one thousand, nine hundred seventeen".
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