51333432410441 has 2 divisors, whose sum is σ = 51333432410442. Its totient is φ = 51333432410440.

The previous prime is 51333432410363. The next prime is 51333432410467. The reversal of 51333432410441 is 14401423433315.

51333432410441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48327231264841 + 3006201145600 = 6951779^2 + 1733840^2 .

It is a cyclic number.

It is not a de Polignac number, because 51333432410441 - 2²² = 51333428216137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51333432410395 and 51333432410404.

It is not a weakly prime, because it can be changed into another prime (51333432410941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25666716205220 + 25666716205221.

It is an arithmetic number, because the mean of its divisors is an integer number (25666716205221).

Almost surely, 2^{51333432410441} is an apocalyptic number.

It is an amenable number.

51333432410441 is a deficient number, since it is larger than the sum of its proper divisors (1).

51333432410441 is an equidigital number, since it uses as much as digits as its factorization.

51333432410441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 38.

Adding to 51333432410441 its reverse (14401423433315), we get a palindrome (65734855843756).

The spelling of 51333432410441 in words is "fifty-one trillion, three hundred thirty-three billion, four hundred thirty-two million, four hundred ten thousand, four hundred forty-one".