Base | Representation |
---|---|
bin | 111010010110111111111011… |
… | …0100101011000001011000111 |
3 | 2111022120021122022001201020120 |
4 | 1310231333312211120023013 |
5 | 1014240432203302302403 |
6 | 5015434312004033023 |
7 | 213061116214423350 |
oct | 16455776645301307 |
9 | 2438507568051216 |
10 | 513334333244103 |
11 | 139622960577268 |
12 | 496a7771692773 |
13 | 190582b2201a57 |
14 | 90a972b32ad27 |
15 | 3e5300d9bbe53 |
hex | 1d2dff69582c7 |
513334333244103 has 64 divisors (see below), whose sum is σ = 801696232243200. Its totient is φ = 286121687005440.
The previous prime is 513334333244099. The next prime is 513334333244153. The reversal of 513334333244103 is 301442333433315.
It is not a de Polignac number, because 513334333244103 - 22 = 513334333244099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513334333244153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6401355738 + ... + 6401435928.
It is an arithmetic number, because the mean of its divisors is an integer number (12526503628800).
Almost surely, 2513334333244103 is an apocalyptic number.
513334333244103 is a deficient number, since it is larger than the sum of its proper divisors (288361898999097).
513334333244103 is a wasteful number, since it uses less digits than its factorization.
513334333244103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126852.
The product of its (nonzero) digits is 1399680, while the sum is 42.
Adding to 513334333244103 its reverse (301442333433315), we get a palindrome (814776666677418).
The spelling of 513334333244103 in words is "five hundred thirteen trillion, three hundred thirty-four billion, three hundred thirty-three million, two hundred forty-four thousand, one hundred three".
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