Base | Representation |
---|---|
bin | 100101010110011100100… |
… | …1100100011100101001111 |
3 | 200011202022122101111021011 |
4 | 1022230321030203211033 |
5 | 1133101244022332003 |
6 | 14530134452550051 |
7 | 1036610364615421 |
oct | 112547114434517 |
9 | 20152278344234 |
10 | 5133445511503 |
11 | 16aa09a187461 |
12 | 6aaa90622327 |
13 | 2b310aa37caa |
14 | 13a6626a8811 |
15 | 8d7ecccc46d |
hex | 4ab3932394f |
5133445511503 has 2 divisors, whose sum is σ = 5133445511504. Its totient is φ = 5133445511502.
The previous prime is 5133445511489. The next prime is 5133445511573. The reversal of 5133445511503 is 3051155443315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5133445511503 - 217 = 5133445380431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5133445511573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566722755751 + 2566722755752.
It is an arithmetic number, because the mean of its divisors is an integer number (2566722755752).
Almost surely, 25133445511503 is an apocalyptic number.
5133445511503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5133445511503 is an equidigital number, since it uses as much as digits as its factorization.
5133445511503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270000, while the sum is 40.
The spelling of 5133445511503 in words is "five trillion, one hundred thirty-three billion, four hundred forty-five million, five hundred eleven thousand, five hundred three".
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