Base | Representation |
---|---|
bin | 10111010110001100100101… |
… | …10000101001001101000111 |
3 | 20201210002001020210002220021 |
4 | 23223012102300221031013 |
5 | 23212124220304024221 |
6 | 301105210513520011 |
7 | 13546131113216665 |
oct | 1353062260511507 |
9 | 221702036702807 |
10 | 51340206314311 |
11 | 153a4294034312 |
12 | 59120ab273007 |
13 | 228548c558035 |
14 | c96c44907c35 |
15 | 5e0723722041 |
hex | 2eb192c29347 |
51340206314311 has 2 divisors, whose sum is σ = 51340206314312. Its totient is φ = 51340206314310.
The previous prime is 51340206314263. The next prime is 51340206314323. The reversal of 51340206314311 is 11341360204315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51340206314311 - 217 = 51340206183239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51340206315311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25670103157155 + 25670103157156.
It is an arithmetic number, because the mean of its divisors is an integer number (25670103157156).
Almost surely, 251340206314311 is an apocalyptic number.
51340206314311 is a deficient number, since it is larger than the sum of its proper divisors (1).
51340206314311 is an equidigital number, since it uses as much as digits as its factorization.
51340206314311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 51340206314311 its reverse (11341360204315), we get a palindrome (62681566518626).
The spelling of 51340206314311 in words is "fifty-one trillion, three hundred forty billion, two hundred six million, three hundred fourteen thousand, three hundred eleven".
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