Base | Representation |
---|---|
bin | 101111110100001011… |
… | …111001110101101011 |
3 | 11220112001220102111002 |
4 | 233310023321311223 |
5 | 1320121344321301 |
6 | 35330320225215 |
7 | 3465200466104 |
oct | 576413716553 |
9 | 156461812432 |
10 | 51341401451 |
11 | 1a85697889a |
12 | 9b4a16b20b |
13 | 4ac29423b2 |
14 | 26b094b3ab |
15 | 150751216b |
hex | bf42f9d6b |
51341401451 has 2 divisors, whose sum is σ = 51341401452. Its totient is φ = 51341401450.
The previous prime is 51341401357. The next prime is 51341401487. The reversal of 51341401451 is 15410414315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51341401451 - 218 = 51341139307 is a prime.
It is not a weakly prime, because it can be changed into another prime (51341406451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25670700725 + 25670700726.
It is an arithmetic number, because the mean of its divisors is an integer number (25670700726).
Almost surely, 251341401451 is an apocalyptic number.
51341401451 is a deficient number, since it is larger than the sum of its proper divisors (1).
51341401451 is an equidigital number, since it uses as much as digits as its factorization.
51341401451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 51341401451 its reverse (15410414315), we get a palindrome (66751815766).
The spelling of 51341401451 in words is "fifty-one billion, three hundred forty-one million, four hundred one thousand, four hundred fifty-one".
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