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51341454403 is a prime number
BaseRepresentation
bin101111110100001100…
…000110110001000011
311220112002000010010021
4233310030012301003
51320121403020103
635330321314311
73465201106351
oct576414066103
9156462003107
1051341454403
111a856a04658
129b4a195997
134ac2960525
1426b09627d1
151507522bbd
hexbf4306c43

51341454403 has 2 divisors, whose sum is σ = 51341454404. Its totient is φ = 51341454402.

The previous prime is 51341454379. The next prime is 51341454413. The reversal of 51341454403 is 30445414315.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51341454403 is a prime.

It is not a weakly prime, because it can be changed into another prime (51341454413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25670727201 + 25670727202.

It is an arithmetic number, because the mean of its divisors is an integer number (25670727202).

Almost surely, 251341454403 is an apocalyptic number.

51341454403 is a deficient number, since it is larger than the sum of its proper divisors (1).

51341454403 is an equidigital number, since it uses as much as digits as its factorization.

51341454403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 51341454403 its reverse (30445414315), we get a palindrome (81786868718).

The spelling of 51341454403 in words is "fifty-one billion, three hundred forty-one million, four hundred fifty-four thousand, four hundred three".