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5134211054241 = 32389716368223
BaseRepresentation
bin100101010110110011011…
…0100110111101010100001
3200011211021222220002110220
41022231212310313222201
51133104331012213431
614530342441113253
71036635351620433
oct112554664675241
920154258802426
105134211054241
1116aa452323005
126ab064a88829
132b3200515169
1413a6d6224653
158d8450e9b96
hex4ab66d37aa1

5134211054241 has 8 divisors (see below), whose sum is σ = 6848480221440. Its totient is φ = 3421374628272.

The previous prime is 5134211054213. The next prime is 5134211054279. The reversal of 5134211054241 is 1424501124315.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5134211054241 - 29 = 5134211053729 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5134211054641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 358176945 + ... + 358191278.

It is an arithmetic number, because the mean of its divisors is an integer number (856060027680).

Almost surely, 25134211054241 is an apocalyptic number.

It is an amenable number.

5134211054241 is a deficient number, since it is larger than the sum of its proper divisors (1714269167199).

5134211054241 is a wasteful number, since it uses less digits than its factorization.

5134211054241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 716370615.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 5134211054241 its reverse (1424501124315), we get a palindrome (6558712178556).

The spelling of 5134211054241 in words is "five trillion, one hundred thirty-four billion, two hundred eleven million, fifty-four thousand, two hundred forty-one".

Divisors: 1 3 2389 7167 716368223 2149104669 1711403684747 5134211054241