Base | Representation |
---|---|
bin | 100101010110110011011… |
… | …0100110111101010100001 |
3 | 200011211021222220002110220 |
4 | 1022231212310313222201 |
5 | 1133104331012213431 |
6 | 14530342441113253 |
7 | 1036635351620433 |
oct | 112554664675241 |
9 | 20154258802426 |
10 | 5134211054241 |
11 | 16aa452323005 |
12 | 6ab064a88829 |
13 | 2b3200515169 |
14 | 13a6d6224653 |
15 | 8d8450e9b96 |
hex | 4ab66d37aa1 |
5134211054241 has 8 divisors (see below), whose sum is σ = 6848480221440. Its totient is φ = 3421374628272.
The previous prime is 5134211054213. The next prime is 5134211054279. The reversal of 5134211054241 is 1424501124315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5134211054241 - 29 = 5134211053729 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5134211054641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 358176945 + ... + 358191278.
It is an arithmetic number, because the mean of its divisors is an integer number (856060027680).
Almost surely, 25134211054241 is an apocalyptic number.
It is an amenable number.
5134211054241 is a deficient number, since it is larger than the sum of its proper divisors (1714269167199).
5134211054241 is a wasteful number, since it uses less digits than its factorization.
5134211054241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 716370615.
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 5134211054241 its reverse (1424501124315), we get a palindrome (6558712178556).
The spelling of 5134211054241 in words is "five trillion, one hundred thirty-four billion, two hundred eleven million, fifty-four thousand, two hundred forty-one".
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