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51342113 is a prime number
BaseRepresentation
bin1100001111011…
…0101100100001
310120121110010202
43003312230201
5101120421423
65032234545
71162254314
oct303665441
9116543122
1051342113
1126a880a9
121523ba55
13a838264
146b6697b
154792728
hex30f6b21

51342113 has 2 divisors, whose sum is σ = 51342114. Its totient is φ = 51342112.

The previous prime is 51342089. The next prime is 51342119. The reversal of 51342113 is 31124315.

51342113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44849809 + 6492304 = 6697^2 + 2548^2 .

It is a cyclic number.

It is not a de Polignac number, because 51342113 - 212 = 51338017 is a prime.

It is not a weakly prime, because it can be changed into another prime (51342119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25671056 + 25671057.

It is an arithmetic number, because the mean of its divisors is an integer number (25671057).

Almost surely, 251342113 is an apocalyptic number.

It is an amenable number.

51342113 is a deficient number, since it is larger than the sum of its proper divisors (1).

51342113 is an equidigital number, since it uses as much as digits as its factorization.

51342113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 360, while the sum is 20.

The square root of 51342113 is about 7165.3410944630. The cubic root of 51342113 is about 371.6703466649.

Adding to 51342113 its reverse (31124315), we get a palindrome (82466428).

The spelling of 51342113 in words is "fifty-one million, three hundred forty-two thousand, one hundred thirteen".