Base | Representation |
---|---|
bin | 111010010111101000111001… |
… | …1101110000111111111100001 |
3 | 2111022212200210002022110121202 |
4 | 1310233101303232013333201 |
5 | 1014243402414000110131 |
6 | 5015542544015330545 |
7 | 213100353004001222 |
oct | 16457216356077741 |
9 | 2438780702273552 |
10 | 513422332035041 |
11 | 1396572085a5370 |
12 | 49700830220a55 |
13 | 19063697545550 |
14 | 90adab8537249 |
15 | 3e5545e2e7bcb |
hex | 1d2f473b87fe1 |
513422332035041 has 16 divisors (see below), whose sum is σ = 611444241018240. Its totient is φ = 424941943547520.
The previous prime is 513422332035001. The next prime is 513422332035061. The reversal of 513422332035041 is 140530233224315.
It is a cyclic number.
It is not a de Polignac number, because 513422332035041 - 238 = 513147454128097 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 513422332034986 and 513422332035004.
It is not an unprimeable number, because it can be changed into a prime (513422332035001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24591537221 + ... + 24591558098.
It is an arithmetic number, because the mean of its divisors is an integer number (38215265063640).
Almost surely, 2513422332035041 is an apocalyptic number.
It is an amenable number.
513422332035041 is a deficient number, since it is larger than the sum of its proper divisors (98021908983199).
513422332035041 is a wasteful number, since it uses less digits than its factorization.
513422332035041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49183095416.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 513422332035041 its reverse (140530233224315), we get a palindrome (653952565259356).
The spelling of 513422332035041 in words is "five hundred thirteen trillion, four hundred twenty-two billion, three hundred thirty-two million, thirty-five thousand, forty-one".
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