Base | Representation |
---|---|
bin | 111010010111101001011001… |
… | …1011101001111100010001111 |
3 | 2111022212210112121102100210001 |
4 | 1310233102303131033202033 |
5 | 1014243412111221220221 |
6 | 5015543242054425131 |
7 | 213100421340020323 |
oct | 16457226335174217 |
9 | 2438783477370701 |
10 | 513423401351311 |
11 | 139657707162520 |
12 | 49700a8a3621a7 |
13 | 19063807c41c79 |
14 | 90adb7a569983 |
15 | 3e554c311c391 |
hex | 1d2f4b374f88f |
513423401351311 has 16 divisors (see below), whose sum is σ = 578172948710400. Its totient is φ = 451686667723200.
The previous prime is 513423401351297. The next prime is 513423401351321. The reversal of 513423401351311 is 113153104324315.
It is a cyclic number.
It is not a de Polignac number, because 513423401351311 - 215 = 513423401318543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513423401351321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19182880 + ... + 37347418.
It is an arithmetic number, because the mean of its divisors is an integer number (36135809294400).
Almost surely, 2513423401351311 is an apocalyptic number.
513423401351311 is a deficient number, since it is larger than the sum of its proper divisors (64749547359089).
513423401351311 is a wasteful number, since it uses less digits than its factorization.
513423401351311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18247470.
The product of its (nonzero) digits is 64800, while the sum is 37.
Adding to 513423401351311 its reverse (113153104324315), we get a palindrome (626576505675626).
The spelling of 513423401351311 in words is "five hundred thirteen trillion, four hundred twenty-three billion, four hundred one million, three hundred fifty-one thousand, three hundred eleven".
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