Base | Representation |
---|---|
bin | 1110111100010101000… |
… | …10100000110011100111 |
3 | 1211002020111111021022012 |
4 | 13132022202200303213 |
5 | 31402443401130203 |
6 | 1031510412224435 |
7 | 52044105663230 |
oct | 7361242406347 |
9 | 1732214437265 |
10 | 513425411303 |
11 | 188819294742 |
12 | 8360916b11b |
13 | 395536ba52c |
14 | 1abc828a087 |
15 | d54e5b7bd8 |
hex | 778a8a0ce7 |
513425411303 has 8 divisors (see below), whose sum is σ = 586778691072. Its totient is φ = 440073829656.
The previous prime is 513425411267. The next prime is 513425411309. The reversal of 513425411303 is 303114524315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 513425411303 - 28 = 513425411047 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 513425411303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513425411309) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 307526 + ... + 1058972.
It is an arithmetic number, because the mean of its divisors is an integer number (73347336384).
Almost surely, 2513425411303 is an apocalyptic number.
513425411303 is a deficient number, since it is larger than the sum of its proper divisors (73353279769).
513425411303 is an equidigital number, since it uses as much as digits as its factorization.
513425411303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 849061.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 513425411303 its reverse (303114524315), we get a palindrome (816539935618).
It can be divided in two parts, 51342 and 5411303, that added together give a palindrome (5462645).
The spelling of 513425411303 in words is "five hundred thirteen billion, four hundred twenty-five million, four hundred eleven thousand, three hundred three".
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