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5134341 = 31711447
BaseRepresentation
bin10011100101100000000101
3100122211222210
4103211200011
52303244331
6302014033
761432632
oct23454005
910584883
105134341
112997563
121877319
1310a9c94
14979189
156b6446
hex4e5805

5134341 has 4 divisors (see below), whose sum is σ = 6845792. Its totient is φ = 3422892.

The previous prime is 5134333. The next prime is 5134361. The reversal of 5134341 is 1434315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5134341 - 23 = 5134333 is a prime.

It is a super-2 number, since 2×51343412 = 52722915008562, which contains 22 as substring.

It is a D-number.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5134301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 855721 + ... + 855726.

It is an arithmetic number, because the mean of its divisors is an integer number (1711448).

Almost surely, 25134341 is an apocalyptic number.

It is an amenable number.

5134341 is a deficient number, since it is larger than the sum of its proper divisors (1711451).

5134341 is a wasteful number, since it uses less digits than its factorization.

5134341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1711450.

The product of its digits is 720, while the sum is 21.

The square root of 5134341 is about 2265.9084270994. The cubic root of 5134341 is about 172.5155457529.

Adding to 5134341 its reverse (1434315), we get a palindrome (6568656).

The spelling of 5134341 in words is "five million, one hundred thirty-four thousand, three hundred forty-one".

Divisors: 1 3 1711447 5134341