Base | Representation |
---|---|
bin | 10111010110010011101011… |
… | …00100011110110101010101 |
3 | 20201210102212110000022121111 |
4 | 23223021311210132311111 |
5 | 23212210013424213013 |
6 | 301111040245215021 |
7 | 13546324320221434 |
oct | 1353116544366525 |
9 | 221712773008544 |
10 | 51344011554133 |
11 | 153a5966a94311 |
12 | 5912991701471 |
13 | 2285947a0842c |
14 | c970c604111b |
15 | 5e089782573d |
hex | 2eb27591ed55 |
51344011554133 has 8 divisors (see below), whose sum is σ = 51415216251680. Its totient is φ = 51272821996560.
The previous prime is 51344011554127. The next prime is 51344011554167. The reversal of 51344011554133 is 33145511044315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51344011554133 - 233 = 51335421619541 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51344011564133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3010738 + ... + 10571308.
It is an arithmetic number, because the mean of its divisors is an integer number (6426902031460).
Almost surely, 251344011554133 is an apocalyptic number.
It is an amenable number.
51344011554133 is a deficient number, since it is larger than the sum of its proper divisors (71204697547).
51344011554133 is an equidigital number, since it uses as much as digits as its factorization.
51344011554133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7569987.
The product of its (nonzero) digits is 216000, while the sum is 40.
Adding to 51344011554133 its reverse (33145511044315), we get a palindrome (84489522598448).
The spelling of 51344011554133 in words is "fifty-one trillion, three hundred forty-four billion, eleven million, five hundred fifty-four thousand, one hundred thirty-three".
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