Base | Representation |
---|---|
bin | 10111010110010101100000… |
… | …11111010010110101100111 |
3 | 20201210112102100001010001101 |
4 | 23223022300133102311213 |
5 | 23212214030003100043 |
6 | 301111322320140531 |
7 | 13546360652256601 |
oct | 1353126037226547 |
9 | 221715370033041 |
10 | 51345000050023 |
11 | 153a6323a6a969 |
12 | 5913008767747 |
13 | 2285a74748244 |
14 | c9717b436171 |
15 | 5e09044d324d |
hex | 2eb2b07d2d67 |
51345000050023 has 2 divisors, whose sum is σ = 51345000050024. Its totient is φ = 51345000050022.
The previous prime is 51345000050017. The next prime is 51345000050093. The reversal of 51345000050023 is 32005000054315.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51345000050023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51345000049973 and 51345000050000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51345000050093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25672500025011 + 25672500025012.
It is an arithmetic number, because the mean of its divisors is an integer number (25672500025012).
Almost surely, 251345000050023 is an apocalyptic number.
51345000050023 is a deficient number, since it is larger than the sum of its proper divisors (1).
51345000050023 is an equidigital number, since it uses as much as digits as its factorization.
51345000050023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 28.
The spelling of 51345000050023 in words is "fifty-one trillion, three hundred forty-five billion, fifty thousand, twenty-three".
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