Base | Representation |
---|---|
bin | 101111110100011010… |
… | …001000011110001111 |
3 | 11220112022220221000121 |
4 | 233310122020132033 |
5 | 1320123323201112 |
6 | 35330532205411 |
7 | 3465244262443 |
oct | 576432103617 |
9 | 156468827017 |
10 | 51345131407 |
11 | 1a858a961a9 |
12 | 9b4b469867 |
13 | 4ac364a07b |
14 | 26b123c823 |
15 | 15079ec407 |
hex | bf468878f |
51345131407 has 4 divisors (see below), whose sum is σ = 51347829960. Its totient is φ = 51342432856.
The previous prime is 51345131401. The next prime is 51345131429. The reversal of 51345131407 is 70413154315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51345131407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51345131401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320532 + ... + 1358857.
It is an arithmetic number, because the mean of its divisors is an integer number (12836957490).
Almost surely, 251345131407 is an apocalyptic number.
51345131407 is a deficient number, since it is larger than the sum of its proper divisors (2698553).
51345131407 is a wasteful number, since it uses less digits than its factorization.
51345131407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2698552.
The product of its (nonzero) digits is 25200, while the sum is 34.
The spelling of 51345131407 in words is "fifty-one billion, three hundred forty-five million, one hundred thirty-one thousand, four hundred seven".
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