513501414133 has 4 divisors (see below), whose sum is σ = 513505967040. Its totient is φ = 513496861228.

The previous prime is 513501414121. The next prime is 513501414203. The reversal of 513501414133 is 331414105315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-513501414133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 513501414095 and 513501414104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (513501414103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2102863 + ... + 2334316.

It is an arithmetic number, because the mean of its divisors is an integer number (128376491760).

Almost surely, 2^513501414133 is an apocalyptic number.

It is an amenable number.

513501414133 is a deficient number, since it is larger than the sum of its proper divisors (4552907).

513501414133 is a wasteful number, since it uses less digits than its factorization.

513501414133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4552906.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 513501414133 its reverse (331414105315), we get a palindrome (844915519448).

The spelling of 513501414133 in words is "five hundred thirteen billion, five hundred one million, four hundred fourteen thousand, one hundred thirty-three".