Base | Representation |
---|---|
bin | 10111010110011111010001… |
… | …10111111110010111001011 |
3 | 20201211000221120211112010122 |
4 | 23223033220313332113023 |
5 | 23212310243144324042 |
6 | 301113550340133455 |
7 | 13546634561561621 |
oct | 1353175067762713 |
9 | 221730846745118 |
10 | 51350241011147 |
11 | 153a85733975a1 |
12 | 591402b99728b |
13 | 22863cb4a3280 |
14 | c975174dd511 |
15 | 5e0b0e6857d2 |
hex | 2eb3e8dfe5cb |
51350241011147 has 8 divisors (see below), whose sum is σ = 55474708323216. Its totient is φ = 47250694952352.
The previous prime is 51350241011137. The next prime is 51350241011171. The reversal of 51350241011147 is 74111014205315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51350241011147 - 216 = 51350240945611 is a prime.
It is not an unprimeable number, because it can be changed into a prime (51350241011107) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6230309033 + ... + 6230317274.
It is an arithmetic number, because the mean of its divisors is an integer number (6934338540402).
Almost surely, 251350241011147 is an apocalyptic number.
51350241011147 is a deficient number, since it is larger than the sum of its proper divisors (4124467312069).
51350241011147 is a wasteful number, since it uses less digits than its factorization.
51350241011147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12460626637.
The product of its (nonzero) digits is 16800, while the sum is 35.
The spelling of 51350241011147 in words is "fifty-one trillion, three hundred fifty billion, two hundred forty-one million, eleven thousand, one hundred forty-seven".
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