Base | Representation |
---|---|
bin | 10111010110100011100011… |
… | …00010000001010001000111 |
3 | 20201211020212100222221021022 |
4 | 23223101301202001101013 |
5 | 23212324442114000341 |
6 | 301115010041141355 |
7 | 13550045441445314 |
oct | 1353216142012107 |
9 | 221736770887238 |
10 | 51352533734471 |
11 | 153a953a598562 |
12 | 591456b78a85b |
13 | 22866a549b2a8 |
14 | c97693bd5d0b |
15 | 5e0be5abae4b |
hex | 2eb471881447 |
51352533734471 has 4 divisors (see below), whose sum is σ = 51352548832200. Its totient is φ = 51352518636744.
The previous prime is 51352533734417. The next prime is 51352533734497. The reversal of 51352533734471 is 17443733525315.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 51352533734471 - 26 = 51352533734407 is a prime.
It is a super-3 number, since 3×513525337344713 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51352533734071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214400 + ... + 10136618.
It is an arithmetic number, because the mean of its divisors is an integer number (12838137208050).
Almost surely, 251352533734471 is an apocalyptic number.
51352533734471 is a deficient number, since it is larger than the sum of its proper divisors (15097729).
51352533734471 is an equidigital number, since it uses as much as digits as its factorization.
51352533734471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15097728.
The product of its digits is 15876000, while the sum is 53.
The spelling of 51352533734471 in words is "fifty-one trillion, three hundred fifty-two billion, five hundred thirty-three million, seven hundred thirty-four thousand, four hundred seventy-one".
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