513654131 has 4 divisors (see below), whose sum is σ = 515306064. Its totient is φ = 512002200.

The previous prime is 513654103. The next prime is 513654137. The reversal of 513654131 is 131456315.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131456315 = 5 ⋅26291263.

It is a cyclic number.

It is not a de Polignac number, because 513654131 - 2¹⁸ = 513391987 is a prime.

It is a super-2 number, since 2×513654131² = 527681132586730322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 513654094 and 513654103.

It is not an unprimeable number, because it can be changed into a prime (513654137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 825500 + ... + 826121.

It is an arithmetic number, because the mean of its divisors is an integer number (128826516).

Almost surely, 2^513654131 is an apocalyptic number.

513654131 is a deficient number, since it is larger than the sum of its proper divisors (1651933).

513654131 is a wasteful number, since it uses less digits than its factorization.

513654131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1651932.

The product of its digits is 5400, while the sum is 29.

The square root of 513654131 is about 22663.9390000944. The cubic root of 513654131 is about 800.8606004391.

The spelling of 513654131 in words is "five hundred thirteen million, six hundred fifty-four thousand, one hundred thirty-one".