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51370213373741 = 291013176522057
BaseRepresentation
bin10111010111000100011110…
…10100011111011100101101
320201212221111111100122222202
423223202033110133130231
523213122144110424431
6301131052241151245
713551242530060163
oct1353421724373455
9221787444318882
1051370213373741
1115405a9225a189
125917a8462b525
1322882622223c2
14c9848dc6d233
155e13ccc928cb
hex2eb88f51f72d

51370213373741 has 4 divisors (see below), whose sum is σ = 51370390186812. Its totient is φ = 51370036560672.

The previous prime is 51370213373719. The next prime is 51370213373749. The reversal of 51370213373741 is 14737331207315.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 23081154361225 + 28289059012516 = 4804285^2 + 5318746^2 .

It is a cyclic number.

It is not a de Polignac number, because 51370213373741 - 230 = 51369139631917 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51370213373749) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87970016 + ... + 88552041.

It is an arithmetic number, because the mean of its divisors is an integer number (12842597546703).

Almost surely, 251370213373741 is an apocalyptic number.

It is an amenable number.

51370213373741 is a deficient number, since it is larger than the sum of its proper divisors (176813071).

51370213373741 is a wasteful number, since it uses less digits than its factorization.

51370213373741 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 176813070.

The product of its (nonzero) digits is 1111320, while the sum is 47.

The spelling of 51370213373741 in words is "fifty-one trillion, three hundred seventy billion, two hundred thirteen million, three hundred seventy-three thousand, seven hundred forty-one".

Divisors: 1 291013 176522057 51370213373741