Base | Representation |
---|---|
bin | 10111010111000110110101… |
… | …01110100010101101010011 |
3 | 20201220001202122220102202221 |
4 | 23223203122232202231103 |
5 | 23213132241443302120 |
6 | 301131421553121511 |
7 | 13551316061316430 |
oct | 1353433256425523 |
9 | 221801678812687 |
10 | 51371478494035 |
11 | 154065813a3847 |
12 | 5918178259297 |
13 | 22884043672ab |
14 | c9856dcb0b87 |
15 | 5e1453d930aa |
hex | 2eb8daba2b53 |
51371478494035 has 8 divisors (see below), whose sum is σ = 70452313363296. Its totient is φ = 35226156681600.
The previous prime is 51371478494033. The next prime is 51371478494051. The reversal of 51371478494035 is 53049487417315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 51371478494035 - 21 = 51371478494033 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51371478494033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 733878264166 + ... + 733878264235.
It is an arithmetic number, because the mean of its divisors is an integer number (8806539170412).
Almost surely, 251371478494035 is an apocalyptic number.
51371478494035 is a deficient number, since it is larger than the sum of its proper divisors (19080834869261).
51371478494035 is a wasteful number, since it uses less digits than its factorization.
51371478494035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1467756528413.
The product of its (nonzero) digits is 50803200, while the sum is 61.
The spelling of 51371478494035 in words is "fifty-one trillion, three hundred seventy-one billion, four hundred seventy-eight million, four hundred ninety-four thousand, thirty-five".
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