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51374347347997 is a prime number
BaseRepresentation
bin10111010111001100001011…
…01110010110100000011101
320201220100011121011022120101
423223212011232112200131
523213204130410113442
6301133014354421101
713551450135216232
oct1353460556264035
9221810147138511
1051374347347997
111540781382a233
125918838b91791
13228877082150b
14c98762cd9789
155e1570b7dcb7
hex2eb985b9681d

51374347347997 has 2 divisors, whose sum is σ = 51374347347998. Its totient is φ = 51374347347996.

The previous prime is 51374347347941. The next prime is 51374347348007. The reversal of 51374347347997 is 79974374347315.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50139017353881 + 1235329994116 = 7080891^2 + 1111454^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51374347347997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51374342347997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25687173673998 + 25687173673999.

It is an arithmetic number, because the mean of its divisors is an integer number (25687173673999).

Almost surely, 251374347347997 is an apocalyptic number.

It is an amenable number.

51374347347997 is a deficient number, since it is larger than the sum of its proper divisors (1).

51374347347997 is an equidigital number, since it uses as much as digits as its factorization.

51374347347997 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1680315840, while the sum is 73.

The spelling of 51374347347997 in words is "fifty-one trillion, three hundred seventy-four billion, three hundred forty-seven million, three hundred forty-seven thousand, nine hundred ninety-seven".