Base | Representation |
---|---|
bin | 10111010111001100001011… |
… | …01110010110100000011101 |
3 | 20201220100011121011022120101 |
4 | 23223212011232112200131 |
5 | 23213204130410113442 |
6 | 301133014354421101 |
7 | 13551450135216232 |
oct | 1353460556264035 |
9 | 221810147138511 |
10 | 51374347347997 |
11 | 1540781382a233 |
12 | 5918838b91791 |
13 | 228877082150b |
14 | c98762cd9789 |
15 | 5e1570b7dcb7 |
hex | 2eb985b9681d |
51374347347997 has 2 divisors, whose sum is σ = 51374347347998. Its totient is φ = 51374347347996.
The previous prime is 51374347347941. The next prime is 51374347348007. The reversal of 51374347347997 is 79974374347315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50139017353881 + 1235329994116 = 7080891^2 + 1111454^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51374347347997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51374342347997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25687173673998 + 25687173673999.
It is an arithmetic number, because the mean of its divisors is an integer number (25687173673999).
Almost surely, 251374347347997 is an apocalyptic number.
It is an amenable number.
51374347347997 is a deficient number, since it is larger than the sum of its proper divisors (1).
51374347347997 is an equidigital number, since it uses as much as digits as its factorization.
51374347347997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1680315840, while the sum is 73.
The spelling of 51374347347997 in words is "fifty-one trillion, three hundred seventy-four billion, three hundred forty-seven million, three hundred forty-seven thousand, nine hundred ninety-seven".
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