Base | Representation |
---|---|
bin | 1001100100101010… |
… | …11110000001000111 |
3 | 111021011210102022212 |
4 | 10302111132001013 |
5 | 41011200043241 |
6 | 2205552214035 |
7 | 241234440641 |
oct | 46225360107 |
9 | 14234712285 |
10 | 5139456071 |
11 | 21a80a8462 |
12 | bb523a31b |
13 | 63ba08489 |
14 | 36a803891 |
15 | 201301beb |
hex | 13255e047 |
5139456071 has 2 divisors, whose sum is σ = 5139456072. Its totient is φ = 5139456070.
The previous prime is 5139456037. The next prime is 5139456107. The reversal of 5139456071 is 1706549315.
Together with next prime (5139456107) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5139456071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5139456571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2569728035 + 2569728036.
It is an arithmetic number, because the mean of its divisors is an integer number (2569728036).
Almost surely, 25139456071 is an apocalyptic number.
5139456071 is a deficient number, since it is larger than the sum of its proper divisors (1).
5139456071 is an equidigital number, since it uses as much as digits as its factorization.
5139456071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 113400, while the sum is 41.
The square root of 5139456071 is about 71689.9997977403. Note that the first 3 decimals coincide. The cubic root of 5139456071 is about 1725.7281609448.
The spelling of 5139456071 in words is "five billion, one hundred thirty-nine million, four hundred fifty-six thousand, seventy-one".
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