Base | Representation |
---|---|
bin | 100101011001011011110… |
… | …1101000110100111000001 |
3 | 200012100212212220122022200 |
4 | 1022302313231012213001 |
5 | 1133202414403040342 |
6 | 14533115340423413 |
7 | 1040225411064654 |
oct | 112626755064701 |
9 | 20170785818280 |
10 | 5139862940097 |
11 | 17018926a7556 |
12 | 6b0181847b69 |
13 | 2b38c1438212 |
14 | 13aab0ad789b |
15 | 8da763bc94c |
hex | 4acb7b469c1 |
5139862940097 has 12 divisors (see below), whose sum is σ = 7450480559184. Its totient is φ = 3414467251800.
The previous prime is 5139862940081. The next prime is 5139862940141. The reversal of 5139862940097 is 7900492689315.
5139862940097 is a `hidden beast` number, since 5 + 139 + 8 + 6 + 2 + 9 + 400 + 97 = 666.
It is not a de Polignac number, because 5139862940097 - 24 = 5139862940081 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5139862940897) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1009000779 + ... + 1009005872.
It is an arithmetic number, because the mean of its divisors is an integer number (620873379932).
It is a 1-persistent number, because it is pandigital, but 2⋅5139862940097 = 10279725880194 is not.
Almost surely, 25139862940097 is an apocalyptic number.
It is an amenable number.
5139862940097 is a deficient number, since it is larger than the sum of its proper divisors (2310617619087).
5139862940097 is a wasteful number, since it uses less digits than its factorization.
5139862940097 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2018006940 (or 2018006937 counting only the distinct ones).
The product of its (nonzero) digits is 29393280, while the sum is 63.
The spelling of 5139862940097 in words is "five trillion, one hundred thirty-nine billion, eight hundred sixty-two million, nine hundred forty thousand, ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •