51400473 has 4 divisors (see below), whose sum is σ = 68533968. Its totient is φ = 34266980.

The previous prime is 51400471. The next prime is 51400501. The reversal of 51400473 is 37400415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51400473 - 2¹ = 51400471 is a prime.

It is not an unprimeable number, because it can be changed into a prime (51400471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8566743 + ... + 8566748.

It is an arithmetic number, because the mean of its divisors is an integer number (17133492).

Almost surely, 2^51400473 is an apocalyptic number.

It is an amenable number.

51400473 is a deficient number, since it is larger than the sum of its proper divisors (17133495).

51400473 is a wasteful number, since it uses less digits than its factorization.

51400473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17133494.

The product of its (nonzero) digits is 1680, while the sum is 24.

The square root of 51400473 is about 7169.4123190119. The cubic root of 51400473 is about 371.8111178359.

Adding to 51400473 its reverse (37400415), we get a palindrome (88800888).

The spelling of 51400473 in words is "fifty-one million, four hundred thousand, four hundred seventy-three".