Base | Representation |
---|---|
bin | 11110101000110… |
… | …010111111111011 |
3 | 1022211012110201022 |
4 | 132220302333323 |
5 | 2023041324011 |
6 | 123001013055 |
7 | 15511010504 |
oct | 3650627773 |
9 | 1284173638 |
10 | 514011131 |
11 | 244167197 |
12 | 12418418b |
13 | 8264c5ca |
14 | 4c3a1bab |
15 | 301d48db |
hex | 1ea32ffb |
514011131 has 2 divisors, whose sum is σ = 514011132. Its totient is φ = 514011130.
The previous prime is 514011089. The next prime is 514011143. The reversal of 514011131 is 131110415.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-514011131 is a prime.
It is a super-2 number, since 2×5140111312 = 528414885583798322, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (514011151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257005565 + 257005566.
It is an arithmetic number, because the mean of its divisors is an integer number (257005566).
Almost surely, 2514011131 is an apocalyptic number.
514011131 is a deficient number, since it is larger than the sum of its proper divisors (1).
514011131 is an equidigital number, since it uses as much as digits as its factorization.
514011131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
The square root of 514011131 is about 22671.8135798617. The cubic root of 514011131 is about 801.0460955713.
Adding to 514011131 its reverse (131110415), we get a palindrome (645121546).
The spelling of 514011131 in words is "five hundred fourteen million, eleven thousand, one hundred thirty-one".
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