Base | Representation |
---|---|
bin | 10011100110111110110011 |
3 | 100200011022022 |
4 | 103212332303 |
5 | 2303443103 |
6 | 302102055 |
7 | 61456412 |
oct | 23467663 |
9 | 10604268 |
10 | 5140403 |
11 | 29a1074 |
12 | 187a92b |
13 | 10ac978 |
14 | 97b479 |
15 | 6b8138 |
hex | 4e6fb3 |
5140403 has 2 divisors, whose sum is σ = 5140404. Its totient is φ = 5140402.
The previous prime is 5140397. The next prime is 5140411. The reversal of 5140403 is 3040415.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5140403 - 28 = 5140147 is a prime.
It is a Sophie Germain prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5140463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2570201 + 2570202.
It is an arithmetic number, because the mean of its divisors is an integer number (2570202).
Almost surely, 25140403 is an apocalyptic number.
5140403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5140403 is an equidigital number, since it uses as much as digits as its factorization.
5140403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 17.
The square root of 5140403 is about 2267.2456858488. The cubic root of 5140403 is about 172.5834141141.
Adding to 5140403 its reverse (3040415), we get a palindrome (8180818).
The spelling of 5140403 in words is "five million, one hundred forty thousand, four hundred three".
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