Base | Representation |
---|---|
bin | 100101011001101110111… |
… | …1011011111010110011101 |
3 | 200012102112120122100011121 |
4 | 1022303131323133112131 |
5 | 1133210223041330121 |
6 | 14533303130050541 |
7 | 1040250326100331 |
oct | 112633573372635 |
9 | 20172476570147 |
10 | 5140504245661 |
11 | 17020916a7954 |
12 | 6b0320579a51 |
13 | 2b3994266975 |
14 | 13ab31d537c1 |
15 | 8dab2849141 |
hex | 4acddedf59d |
5140504245661 has 2 divisors, whose sum is σ = 5140504245662. Its totient is φ = 5140504245660.
The previous prime is 5140504245649. The next prime is 5140504245677. The reversal of 5140504245661 is 1665424050415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3106512000900 + 2033992244761 = 1762530^2 + 1426181^2 .
It is a cyclic number.
It is not a de Polignac number, because 5140504245661 - 25 = 5140504245629 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5140504245691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2570252122830 + 2570252122831.
It is an arithmetic number, because the mean of its divisors is an integer number (2570252122831).
Almost surely, 25140504245661 is an apocalyptic number.
It is an amenable number.
5140504245661 is a deficient number, since it is larger than the sum of its proper divisors (1).
5140504245661 is an equidigital number, since it uses as much as digits as its factorization.
5140504245661 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576000, while the sum is 43.
The spelling of 5140504245661 in words is "five trillion, one hundred forty billion, five hundred four million, two hundred forty-five thousand, six hundred sixty-one".
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