Base | Representation |
---|---|
bin | 101111110111111111… |
… | …111001010001111111 |
3 | 11220200112020222021112 |
4 | 233313333321101333 |
5 | 1320234233043203 |
6 | 35340523152235 |
7 | 3466605240641 |
oct | 576777712177 |
9 | 156615228245 |
10 | 51405362303 |
11 | 1a889a945a9 |
12 | 9b6767567b |
13 | 4b02c78159 |
14 | 26b923a891 |
15 | 150ce486d8 |
hex | bf7ff947f |
51405362303 has 4 divisors (see below), whose sum is σ = 51476071920. Its totient is φ = 51334652688.
The previous prime is 51405362299. The next prime is 51405362317. The reversal of 51405362303 is 30326350415.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51405362303 - 22 = 51405362299 is a prime.
It is a super-2 number, since 2×514053623032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 51405362303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51405362363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35353718 + ... + 35355171.
It is an arithmetic number, because the mean of its divisors is an integer number (12869017980).
Almost surely, 251405362303 is an apocalyptic number.
51405362303 is a deficient number, since it is larger than the sum of its proper divisors (70709617).
51405362303 is an equidigital number, since it uses as much as digits as its factorization.
51405362303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70709616.
The product of its (nonzero) digits is 32400, while the sum is 32.
The spelling of 51405362303 in words is "fifty-one billion, four hundred five million, three hundred sixty-two thousand, three hundred three".
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