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51408001 is a prime number
BaseRepresentation
bin1100010000011…
…0110010000001
310120201210112001
43010012302001
5101130024001
65033504001
71162650361
oct304066201
9116653461
1051408001
1127022657
1215272001
13a85c248
146b829a1
1547a7001
hex3106c81

51408001 has 2 divisors, whose sum is σ = 51408002. Its totient is φ = 51408000.

The previous prime is 51407999. The next prime is 51408011. The reversal of 51408001 is 10080415.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50410000 + 998001 = 7100^2 + 999^2 .

It is a cyclic number.

It is not a de Polignac number, because 51408001 - 21 = 51407999 is a prime.

Together with 51407999, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 51408001.

It is not a weakly prime, because it can be changed into another prime (51408011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25704000 + 25704001.

It is an arithmetic number, because the mean of its divisors is an integer number (25704001).

Almost surely, 251408001 is an apocalyptic number.

It is an amenable number.

51408001 is a deficient number, since it is larger than the sum of its proper divisors (1).

51408001 is an equidigital number, since it uses as much as digits as its factorization.

51408001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 160, while the sum is 19.

The square root of 51408001 is about 7169.9373079547. The cubic root of 51408001 is about 371.8292684954.

Adding to 51408001 its reverse (10080415), we get a palindrome (61488416).

The spelling of 51408001 in words is "fifty-one million, four hundred eight thousand, one".