Base | Representation |
---|---|
bin | 1001100100110101… |
… | …10111011001100001 |
3 | 111021021110021220111 |
4 | 10302122313121201 |
5 | 41012030331003 |
6 | 2210042411321 |
7 | 241252452244 |
oct | 46232673141 |
9 | 14237407814 |
10 | 5140870753 |
11 | 21a8984317 |
12 | bb5800b41 |
13 | 63c0b2375 |
14 | 36aa9125b |
15 | 2014d0e6d |
hex | 1326b7661 |
5140870753 has 2 divisors, whose sum is σ = 5140870754. Its totient is φ = 5140870752.
The previous prime is 5140870739. The next prime is 5140870789. The reversal of 5140870753 is 3570780415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3979969569 + 1160901184 = 63087^2 + 34072^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5140870753 is a prime.
It is a super-3 number, since 3×51408707533 (a number of 30 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (5140870453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2570435376 + 2570435377.
It is an arithmetic number, because the mean of its divisors is an integer number (2570435377).
Almost surely, 25140870753 is an apocalyptic number.
It is an amenable number.
5140870753 is a deficient number, since it is larger than the sum of its proper divisors (1).
5140870753 is an equidigital number, since it uses as much as digits as its factorization.
5140870753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 117600, while the sum is 40.
The square root of 5140870753 is about 71699.8657809065. The cubic root of 5140870753 is about 1725.8864872063.
The spelling of 5140870753 in words is "five billion, one hundred forty million, eight hundred seventy thousand, seven hundred fifty-three".
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