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514101300052999 is a prime number
BaseRepresentation
bin111010011100100101000100…
…1010111100100010000000111
32111102021121022112102110212211
41310321022021113210100013
51014341013430303143444
65021222513220324251
7213200410320634651
oct16471121127442007
92442247275373784
10514101300052999
1113989915631761a
12497b0339243687
13190b27105804a9
1490d48c84816d1
153e67e4bc36c34
hex1d392895e4407

514101300052999 has 2 divisors, whose sum is σ = 514101300053000. Its totient is φ = 514101300052998.

The previous prime is 514101300052897. The next prime is 514101300053069. The reversal of 514101300052999 is 999250003101415.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-514101300052999 is a prime.

It is a super-3 number, since 3×5141013000529993 (a number of 45 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (514101300052099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257050650026499 + 257050650026500.

It is an arithmetic number, because the mean of its divisors is an integer number (257050650026500).

Almost surely, 2514101300052999 is an apocalyptic number.

514101300052999 is a deficient number, since it is larger than the sum of its proper divisors (1).

514101300052999 is an equidigital number, since it uses as much as digits as its factorization.

514101300052999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 437400, while the sum is 49.

The spelling of 514101300052999 in words is "five hundred fourteen trillion, one hundred one billion, three hundred million, fifty-two thousand, nine hundred ninety-nine".