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51412424502541 is a prime number
BaseRepresentation
bin10111011000010011000110…
…10011001010110100001101
320202000222110021001011222111
423230021203103022310031
523214320121133040131
6301202313004144021
713554265543540504
oct1354114323126415
9222028407034874
1051412424502541
1115421983348aa3
1259240a4b38011
13228c22b4018ab
14c9a535d7383b
155e254d943ab1
hex2ec2634cad0d

51412424502541 has 2 divisors, whose sum is σ = 51412424502542. Its totient is φ = 51412424502540.

The previous prime is 51412424502503. The next prime is 51412424502559. The reversal of 51412424502541 is 14520542421415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34614148457641 + 16798276044900 = 5883379^2 + 4098570^2 .

It is a cyclic number.

It is not a de Polignac number, because 51412424502541 - 221 = 51412422405389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51412424502494 and 51412424502503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51412424512541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25706212251270 + 25706212251271.

It is an arithmetic number, because the mean of its divisors is an integer number (25706212251271).

Almost surely, 251412424502541 is an apocalyptic number.

It is an amenable number.

51412424502541 is a deficient number, since it is larger than the sum of its proper divisors (1).

51412424502541 is an equidigital number, since it uses as much as digits as its factorization.

51412424502541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256000, while the sum is 40.

Adding to 51412424502541 its reverse (14520542421415), we get a palindrome (65932966923956).

The spelling of 51412424502541 in words is "fifty-one trillion, four hundred twelve billion, four hundred twenty-four million, five hundred two thousand, five hundred forty-one".