Base | Representation |
---|---|
bin | 100101011010010110100… |
… | …0111100110001101011111 |
3 | 200012112222011120212220222 |
4 | 1022310231013212031133 |
5 | 1133220433200211201 |
6 | 14534043030031555 |
7 | 1040325260556521 |
oct | 112645507461537 |
9 | 20175864525828 |
10 | 5141832819551 |
11 | 17027036410aa |
12 | 6b06314a85bb |
13 | 2b3b4659776c |
14 | 13ac1a591a11 |
15 | 8db3e2d091b |
hex | 4ad2d1e635f |
5141832819551 has 4 divisors (see below), whose sum is σ = 5141871581400. Its totient is φ = 5141794057704.
The previous prime is 5141832819511. The next prime is 5141832819559. The reversal of 5141832819551 is 1559182381415.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5141832819551 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5141832819493 and 5141832819502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5141832819559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19181261 + ... + 19447478.
It is an arithmetic number, because the mean of its divisors is an integer number (1285467895350).
Almost surely, 25141832819551 is an apocalyptic number.
5141832819551 is a deficient number, since it is larger than the sum of its proper divisors (38761849).
5141832819551 is a wasteful number, since it uses less digits than its factorization.
5141832819551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38761848.
The product of its digits is 1728000, while the sum is 53.
The spelling of 5141832819551 in words is "five trillion, one hundred forty-one billion, eight hundred thirty-two million, eight hundred nineteen thousand, five hundred fifty-one".
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