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51431213341 = 372531549203
BaseRepresentation
bin101111111001100010…
…100000100100011101
311220202022220100020101
4233321202200210131
51320312342311331
635343245221101
73500341046254
oct577142404435
9156668810211
1051431213341
111a8a26408a2
129b74261791
134b08429821
1426bc84979b
151510353061
hexbf98a091d

51431213341 has 8 divisors (see below), whose sum is σ = 52842212064. Its totient is φ = 50021318160.

The previous prime is 51431213333. The next prime is 51431213389. The reversal of 51431213341 is 14331213415.

51431213341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51431213341 - 23 = 51431213333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51431213641) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 180955 + ... + 368248.

It is an arithmetic number, because the mean of its divisors is an integer number (6605276508).

Almost surely, 251431213341 is an apocalyptic number.

It is an amenable number.

51431213341 is a deficient number, since it is larger than the sum of its proper divisors (1410998723).

51431213341 is a wasteful number, since it uses less digits than its factorization.

51431213341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 551771.

The product of its digits is 4320, while the sum is 28.

Adding to 51431213341 its reverse (14331213415), we get a palindrome (65762426756).

The spelling of 51431213341 in words is "fifty-one billion, four hundred thirty-one million, two hundred thirteen thousand, three hundred forty-one".

Divisors: 1 37 2531 93647 549203 20320511 1390032793 51431213341