Base | Representation |
---|---|
bin | 101111111001101010… |
… | …111011011000001101 |
3 | 11220202111001110121122 |
4 | 233321222323120031 |
5 | 1320313423422201 |
6 | 35343404410325 |
7 | 3500365600454 |
oct | 577152733015 |
9 | 156674043548 |
10 | 51433420301 |
11 | 1a8a3908a2a |
12 | 9b74b469a5 |
13 | 4b08a20213 |
14 | 26bcc61b9b |
15 | 151063be1b |
hex | bf9abb60d |
51433420301 has 2 divisors, whose sum is σ = 51433420302. Its totient is φ = 51433420300.
The previous prime is 51433420289. The next prime is 51433420309. The reversal of 51433420301 is 10302433415.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38590638025 + 12842782276 = 196445^2 + 113326^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51433420301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51433420309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25716710150 + 25716710151.
It is an arithmetic number, because the mean of its divisors is an integer number (25716710151).
Almost surely, 251433420301 is an apocalyptic number.
It is an amenable number.
51433420301 is a deficient number, since it is larger than the sum of its proper divisors (1).
51433420301 is an equidigital number, since it uses as much as digits as its factorization.
51433420301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 51433420301 its reverse (10302433415), we get a palindrome (61735853716).
The spelling of 51433420301 in words is "fifty-one billion, four hundred thirty-three million, four hundred twenty thousand, three hundred one".
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