51433431241 has 4 divisors (see below), whose sum is σ = 51437588500. Its totient is φ = 51429273984.

The previous prime is 51433431239. The next prime is 51433431271. The reversal of 51433431241 is 14213433415.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14213433415 = 5 ⋅2842686683.

It can be written as a sum of positive squares in 2 ways, for example, as 5154665616 + 46278765625 = 71796^2 + 215125^2 .

It is a cyclic number.

It is not a de Polignac number, because 51433431241 - 2¹ = 51433431239 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51433431221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2060016 + ... + 2084833.

It is an arithmetic number, because the mean of its divisors is an integer number (12859397125).

Almost surely, 2^51433431241 is an apocalyptic number.

It is an amenable number.

51433431241 is a deficient number, since it is larger than the sum of its proper divisors (4157259).

51433431241 is a wasteful number, since it uses less digits than its factorization.

51433431241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4157258.

The product of its digits is 17280, while the sum is 31.

Adding to 51433431241 its reverse (14213433415), we get a palindrome (65646864656).

The spelling of 51433431241 in words is "fifty-one billion, four hundred thirty-three million, four hundred thirty-one thousand, two hundred forty-one".