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51433442431 = 77347634633
BaseRepresentation
bin101111111001101011…
…000000110001111111
311220202111002120222021
4233321223000301333
51320313430124211
635343405101011
73500366022130
oct577153006177
9156674076867
1051433442431
111a8a3923618
129b74b57767
134b08a2a307
1426bcc69c87
151510643771
hexbf9ac0c7f

51433442431 has 4 divisors (see below), whose sum is σ = 58781077072. Its totient is φ = 44085807792.

The previous prime is 51433442341. The next prime is 51433442441. The reversal of 51433442431 is 13424433415.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51433442431 - 217 = 51433311359 is a prime.

It is a super-2 number, since 2×514334424312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51433442441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3673817310 + ... + 3673817323.

It is an arithmetic number, because the mean of its divisors is an integer number (14695269268).

Almost surely, 251433442431 is an apocalyptic number.

51433442431 is a deficient number, since it is larger than the sum of its proper divisors (7347634641).

51433442431 is an equidigital number, since it uses as much as digits as its factorization.

51433442431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7347634640.

The product of its digits is 69120, while the sum is 34.

Adding to 51433442431 its reverse (13424433415), we get a palindrome (64857875846).

The spelling of 51433442431 in words is "fifty-one billion, four hundred thirty-three million, four hundred forty-two thousand, four hundred thirty-one".

Divisors: 1 7 7347634633 51433442431