5143414053133 has 2 divisors, whose sum is σ = 5143414053134. Its totient is φ = 5143414053132.

The previous prime is 5143414053097. The next prime is 5143414053221. The reversal of 5143414053133 is 3313504143415.

5143414053133 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4615265932489 + 528148120644 = 2148317^2 + 726738^2 .

It is a cyclic number.

It is not a de Polignac number, because 5143414053133 - 2¹³ = 5143414044941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5143414053092 and 5143414053101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5143414056133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2571707026566 + 2571707026567.

It is an arithmetic number, because the mean of its divisors is an integer number (2571707026567).

Almost surely, 2^{5143414053133} is an apocalyptic number.

It is an amenable number.

5143414053133 is a deficient number, since it is larger than the sum of its proper divisors (1).

5143414053133 is an equidigital number, since it uses as much as digits as its factorization.

5143414053133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 5143414053133 its reverse (3313504143415), we get a palindrome (8456918196548).

The spelling of 5143414053133 in words is "five trillion, one hundred forty-three billion, four hundred fourteen million, fifty-three thousand, one hundred thirty-three".