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51434204399957 is a prime number
BaseRepresentation
bin10111011000111011101010…
…11110111000100101010101
320202010001200010202121110202
423230131311132320211111
523220144222311244312
6301220314115030245
713555666350604631
oct1354356536704525
9222101603677422
1051434204399957
111543013a551315
125928362b9b385
1322912bc77b562
14c9b6007bbdc1
155e2dc5a969c2
hex2ec7757b8955

51434204399957 has 2 divisors, whose sum is σ = 51434204399958. Its totient is φ = 51434204399956.

The previous prime is 51434204399749. The next prime is 51434204400031. The reversal of 51434204399957 is 75999340243415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51132238763761 + 301965636196 = 7150681^2 + 549514^2 .

It is a cyclic number.

It is not a de Polignac number, because 51434204399957 - 210 = 51434204398933 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51434204399893 and 51434204399902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51434204399057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25717102199978 + 25717102199979.

It is an arithmetic number, because the mean of its divisors is an integer number (25717102199979).

Almost surely, 251434204399957 is an apocalyptic number.

It is an amenable number.

51434204399957 is a deficient number, since it is larger than the sum of its proper divisors (1).

51434204399957 is an equidigital number, since it uses as much as digits as its factorization.

51434204399957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 146966400, while the sum is 65.

The spelling of 51434204399957 in words is "fifty-one trillion, four hundred thirty-four billion, two hundred four million, three hundred ninety-nine thousand, nine hundred fifty-seven".