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51440273151 = 3307409136559
BaseRepresentation
bin101111111010000101…
…000100011011111111
311220202221221121221220
4233322011010123333
51320322202220101
635344211324423
73500511051561
oct577205043377
9156687847856
1051440273151
111a8a7769643
129b772b0713
134b0a27c467
1426bdb27331
151511042636
hexbfa1446ff

51440273151 has 16 divisors (see below), whose sum is σ = 68979187200. Its totient is φ = 34097986368.

The previous prime is 51440273149. The next prime is 51440273153. The reversal of 51440273151 is 15137204415.

It is an interprime number because it is at equal distance from previous prime (51440273149) and next prime (51440273153).

It is not a de Polignac number, because 51440273151 - 21 = 51440273149 is a prime.

It is a super-2 number, since 2×514402731512 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51440273153) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 308410 + ... + 444968.

It is an arithmetic number, because the mean of its divisors is an integer number (4311199200).

Almost surely, 251440273151 is an apocalyptic number.

51440273151 is a deficient number, since it is larger than the sum of its proper divisors (17538914049).

51440273151 is a wasteful number, since it uses less digits than its factorization.

51440273151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137278.

The product of its (nonzero) digits is 16800, while the sum is 33.

Adding to 51440273151 its reverse (15137204415), we get a palindrome (66577477566).

The spelling of 51440273151 in words is "fifty-one billion, four hundred forty million, two hundred seventy-three thousand, one hundred fifty-one".

Divisors: 1 3 307 409 921 1227 125563 136559 376689 409677 41923613 55852631 125770839 167557893 17146757717 51440273151