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5144131025421 = 31714710341807
BaseRepresentation
bin100101011011011011000…
…0110100011101000001101
3200012202220100001211200220
41022312312012203220031
51133240140020303141
614535103044341553
71040436235156263
oct112666606435015
920182810054626
105144131025421
1117036829471a3
126b0b730a48b9
132b41217620ab
1413ad978b4433
158dc25e4a766
hex4adb61a3a0d

5144131025421 has 4 divisors (see below), whose sum is σ = 6858841367232. Its totient is φ = 3429420683612.

The previous prime is 5144131025417. The next prime is 5144131025503. The reversal of 5144131025421 is 1245201314415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5144131025421 - 22 = 5144131025417 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5144131025821) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857355170901 + ... + 857355170906.

It is an arithmetic number, because the mean of its divisors is an integer number (1714710341808).

Almost surely, 25144131025421 is an apocalyptic number.

It is an amenable number.

5144131025421 is a deficient number, since it is larger than the sum of its proper divisors (1714710341811).

5144131025421 is a wasteful number, since it uses less digits than its factorization.

5144131025421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1714710341810.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 5144131025421 its reverse (1245201314415), we get a palindrome (6389332339836).

The spelling of 5144131025421 in words is "five trillion, one hundred forty-four billion, one hundred thirty-one million, twenty-five thousand, four hundred twenty-one".

Divisors: 1 3 1714710341807 5144131025421