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5144443303 = 51131100613
BaseRepresentation
bin1001100101010000…
…11111100110100111
3111021112011210112011
410302220133212213
541013434141203
62210251135051
7241325021656
oct46250374647
914245153464
105144443303
1121aa9a443a
12bb6a44487
1363ca634bc
1436b34119d
1520198976d
hex132a1f9a7

5144443303 has 4 divisors (see below), whose sum is σ = 5144595048. Its totient is φ = 5144291560.

The previous prime is 5144443289. The next prime is 5144443387. The reversal of 5144443303 is 3033444415.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5144443303 - 213 = 5144435111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5144443903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 825 + ... + 101437.

It is an arithmetic number, because the mean of its divisors is an integer number (1286148762).

Almost surely, 25144443303 is an apocalyptic number.

5144443303 is a deficient number, since it is larger than the sum of its proper divisors (151745).

5144443303 is a wasteful number, since it uses less digits than its factorization.

5144443303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151744.

The product of its (nonzero) digits is 34560, while the sum is 31.

The square root of 5144443303 is about 71724.7746807196. The cubic root of 5144443303 is about 1726.2861852565.

Adding to 5144443303 its reverse (3033444415), we get a palindrome (8177887718).

The spelling of 5144443303 in words is "five billion, one hundred forty-four million, four hundred forty-three thousand, three hundred three".

Divisors: 1 51131 100613 5144443303